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CSIR-NET 2017 DEC(46)

21 comments

CSIR-NET

46. Youngs modulus of a rock specimen of density 2.7 gm/cc is 9.72 megabar. The longitudinal wave velocity (in km/s) in the rock is 

1. 4.8
2. 5.2
3. 6.0
4. 7.2

Solution:
Using Young's modulus we can calculate the Bulk modulus and rigidity modulus and then finally we can calculate the P-wave velocity (Please check it comment section).  In this case I'm not getting the answer.

If I calculate the One-dimensional Wave velocity, 

Wave Velocity  (V) = √(E/ ρ) -------------------(1)

E-Young's modulus = 9.72 megabar

                            = 9.72 *106 bar

                            =9.72* 1011 pascal

                           =972* 109 pascal

Density = 2.7 gm/cc

              =2700 kg/m3

Above valuses substitute in eq(1)

V = √ (972*109 /2700)

V = √ (36*107)

V=6000 m/s

V = 6 km/s

( I am getting one zero extra. If anyone knows please correct this problem)



Another solution:

Thanks to Rohit Jha,

 

Using Inverse Gardner equation from density in $\rho$ gm/cc and velocity of the longitudinal wave is in m/s


Given values,


$\rho$=2.7 gm/cc


What is $V_p$ is in m/s?

 

$V_p=108 \rho^4$

 

$V_p=108 (2.7)^4$

 

$V_p=5739.56 m/s$

 

Therefore $V_p=5.739 km/s$



Reference :Gardner's equation - SubSurfWiki



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21 comments

  1. Super Brother. You are doing Good Job really, Keep it up.

    ReplyDelete
  2. Given youngs modulus not bulk .. still nice work keep it up .

    ReplyDelete
  3. It's given young's modulus not bulk modulus sir.By putting Young's modulus formula it's not giving any of the given value. Please help me out for this. Thank you

    ReplyDelete
    Replies
    1. use K= E/3(1-2v),
      K bulk modulus
      E young's modulus
      v poisson's ratio (0.25 for ideal case)

      for this values

      k= 648*10^9

      submit this value in Vp^2= (k/p)

      p- density

      Answer for this: 4.8 km/s (please check it once)

      Delete
    2. If you like this blog, please follow me.. Please share your solution..

      Delete
  4. Very good job. Thank you for solution.
    But

    VP = √ (36*107)

    VP=6000 m/s.... How is it come.

    VP = √ (36*107) = 6000*√ (10).......Please check it.

    ReplyDelete
    Replies
    1. Please check above comment which I was posted , in this first we have to calculate bulk modulus using Young's modulus, then we will calculate the longitudinal velocity ...

      Delete
  5. First we need to calculate bulk modulus using young's modulus, then we need to calculate shear modulus using bulk modulus, then substitute in the Vp formula and the answer will come 20.7 km/sec....need to change bar into pascal and gm/cc into kg/m3

    ReplyDelete
    Replies
    1. But one more thing we have to consider, no where in the earth the the P-wave velocity is 20km/s.

      Delete
    2. Sir, what he said is correct. We have to solve it like that. But i am getting 2.0 km/sec

      Delete
  6. why havent you considered the rigidity modulus here

    ReplyDelete
  7. Use Gardner equation
    Vp= 108*(density)^4 m/sec

    Vp= 108*(2.7)^4
    Vp= 5739.36 m/s
    Vp= 5.739 km/s
    Vp=6km/s(Approx)

    ReplyDelete
    Replies
    1. Thank you Rohit. Please send me name of the reference text book.

      Delete
  8. https://www.subsurfwiki.org/wiki/Gardner%27s_equation#:~:text=Gardner's%20equation%20is%20an%20empirical,when%20performing%20a%20well%20tie).

    ReplyDelete
    Replies
    1. Thank you so much Rohit. So In this case we won't consider the Young's modulus right. I will update your solution also.

      Delete

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