Introduction to gpsurya blog

$Dear$ $Friends,$ In this blog you will find around 320 solved Geophysics GATE and CSIR-NET and other competitive exams solutions with a better explanation. Please follow and share if you like it. $Thanks,$ $gpsurya$ and $group$

CSIR-NET 2017 DEC 106

1 comment

106. A planet is 11 times the radius of the Earth in size, but one-fourth in mass density. The gravity field on its surface would be around (in gals)

A) 1600

B) 2700

C) 3300

D) 3500



Solution:

Earth radius = rE

Planet radius = rp = 11* rE


Earth density = ρE

Planet density = ρP = ρE /4


Gravity of the planet gP = G m / r2 -------------(1)



Desnity = Mass / Volume


Mass = Density * Volume

       = (4/3 * Π * r3 * ρ)


Substitute above values in eq (1)

gp = (G * 4/3 * П * r3 * ρ) / r2


gp = (G * 4/3 * П * r * ρ)


gp = (6.67*10-11 * 4/3 * 3.14 * 11* 6371000* 1/4 *5500) km /s2


gp =322 /12 m/s^2


gp = 26.83 m/s2


gp = 2683 cm/s2 ( cm/s2 = gal )

Related Posts

1 comment

  1. Great Post! Guru Institute has become one of the most preferred institutes for CSIR NET Coaching in Chandigarh.

    ReplyDelete

Post a Comment

Subscribe Our Newsletter