GATE-2008
37.
The dip slip of fault is 200m and the dip amount is 30°. The throw
of the fault (m) is.
(A)
300 (B) 200 (C) 100
(D) 5
Solution:
Dip
slip of a fault = 200m
Dip
= 30°
sinθ=
Throw/ slip -----------------(1)
Throw
= sin30° * 200
=
200/ 2 (sin30°= 1/2)
Therefore
Throw= 100 m.
Fault
Motion Terms:
1.
Throw
The
vertical amount of fault motion; the elevation difference between two
points offset by the fault.
2.
Heave
The
horizontal amount of fault motion perpendicular to the strike of the
fault.
3.
Strike Slip
The
horizontal amount of fault motion parallel to the strike of the
fault.
4.
Dip Slip
The
amount of fault motion in the dip direction of the fault plane;
(Dip slip)2 =
(heave)2 + (Throw)2
5.
Net Slip
The
total amount of fault motion:
(Net slip)2 =
(Strike slip)2 + (Dip slip)2
Reference : http://www.geosci.usyd.edu.au/users/prey/Teaching/Geos-2123/Faults/Sld11.html#
Reference : http://www.geosci.usyd.edu.au/users/prey/Teaching/Geos-2123/Faults/Sld11.html#
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excellent diagram for explaining all terms in single pic
ReplyDeleteThank you so much venkata shiva....
DeleteThe hanging wall block is displaced by 10 meters towards the East direction on a fault plane with attitude 030/70° SE. Find the pitch of the net slip on the fault plane. (2 places of decimal)
ReplyDelete