GATE-2007
Q.49:-
A P-wave incident on a horizontal interface between two layers at an
angle of 30° generates a reflected S-wave .What is the angle of
reflection of the S-wave ?( The P and S-wave velocities in the top
layers are 4km/s and 2.5km/s respectively).
Solution:
Formula:
using Snells law
-
$\frac{Sin I}{Sin r}=\frac{V1{}}{V2}$ ( is called the law of refraction for plane seismic waves)
-
$\frac{Sin Ip}{Vp1}=\frac{Sin Is}{Vs1}=\frac{Sin Rp}{Vp2}=\frac{Sin Rs}{Vs2}$
Using the second formula
$\frac{Sin Ip}{Vp1}=\frac{Sin Rs}{Vs2}$
Rs is the angle of reflection
of the S- wave
Given
values are:-
Incident
angle of P- wave =30º
Velocities
of P-and S waves are
Vp=
4km/s and Vs=2.5 km/s
$\frac{Sin 30}{4}=\frac{Sin
Rs}{2.5}$
$\frac{0.5}{4}=\frac{Sin
Rs}{2.5}$
$Sin Rs =\frac{2.5*0.5}{4}$
$Rs=\arcsin(0.3125)$
Rs=18.179
Angle
of reflection of a S-wave is =18.179º
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