22. In order to have the same value of the surface acceleration due to
gravity as on earth, a planet twice its radius must have a mean relative
density of.
1)2.75
2)5.5
3)1.4
4)2.25
Formula:
acceleration due to gravity g= (G*m) /r2 -----------------(1)
Form the above problem, we need a relation between the radius and
density
So,
Density = mass / Volume
mass= Density * Volume
m= ρ * v ---------------(2)
Substitute eq (2) in eq (1)
g = (G*ρ*v) / r2
then,
(G*ρ1*v1) / r12 = (G*ρ2*v2)
/ r22 -------------------(3)
Volume of the Earth and planets are v= 4/3 * (П* r3)
substitute in equation (3)
(G*ρ1* 4/3 * (П* r13) ) / r12 =
(G*ρ2* 4/3 * (П* r23) ) / r22
Therefore, simplifying above equation, we get,
ρ1*r1 = ρ2* r2
(ρ2 /ρ1) = (r1 /r2)
----------------(4)
from above problem
r2= 2*r1
ρ1= 5.5 gm/cc earth density
substitute above values in equation (4)
(ρ2 /ρ1) = (r1 /2*r1)
= 1/2
ρ2= 5.5 /2
ρ2 =2.75 gm/cc
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