GATE-2008
69. In electrical logging, the measured resistivity of flushed zone is 19.2 Ωm, the resistivity of mud filtrate is 1.33 Ωm and the computed value of residual oil saturation in flushed zone is 20%. The value of formation resistivity factor is
A) 8.50
B)8.85
C)9.11
D)9.24
B)8.85
C)9.11
D)9.24
Solution:
The residual water
saturation (Swr) = ?
Formation factor (F)
= ?
Resistivity of
flushed zone (Rxo)= 19.2 Ωm
Resistivity of mud
filtrate (Rmf) = 1.33 Ωm
Residual
oil saturation (Sor)
= 20%
= 20 /
100
=0.2
Swr
= 1- Sor
=
1- 0.2
=
0.8
Formula:
(Swr)2
= (F
* Rmf)
/ Rxo
---------------------(1)
F=
((Swr)2
* Rxo
)/
Rmf
F=
(0.8)2
* 19.2 / 1.33
F=
0.64 * 19.2 / 1.33
F=
9.239
Formation
factor (F) = 9.24
THANK YOU BRO
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