CSIR-NET
2013
82.
A thrust dipping 30° caused a vertical uplift of a rock surface by
100m in 20,000years .What are the magnitude and rate of slip along
the thrust?
A)
200m and 20cm/year
B)
100m and 0.5 cm/year
C)
200m and 1 cm/year
D)
No slip along the thrust
Solution:
Dip
slip of a fault = ?
Dip
= 30°
Throw
= 100 m
sinθ=
Throw/ slip -----------------(1)
sin30°=
100 / slip
Slip
= 100 / sin30°
Slip
= 100 *2 (sin30°= 1/2)
Slip
= 200 m
Rate
of slip along the fault = distance / time
(Slip)
distance = 200 m
time
= 20,000 years
Rate
of slip (velocity) = 200 / 20,000
=
2/ 200
=
0.01 m/ year
=
1 cm/ year
Therefore,Rate
of slip along the thrust = 1 cm/ year
){kind=link}
Post a Comment
Post a Comment