GATE
2018
76)
A plane electromagnetic (EM) wave traveling vertically downwards
with a frequency of 1000Hz in a homogeneous medium has a skin depth
of 100m. The ratio of the amplitude of the EM wave at a depth of 75m
with respect to the amplitude at the Earth’s surface is
______________
(Thanks to Neeraja, AU)
(Thanks to Neeraja, AU)
Solution:
$A(Z) = A_o e^{-\beta Z} -----(1)$
$A(Z) = A_o e^{-\beta Z} -----(1)$
A(Z)
– amplitude of EM at a depth Z
$A_o – amplitude of EM wave at Earth’s surface(Z=0)$
$A_o – amplitude of EM wave at Earth’s surface(Z=0)$
$\beta – decay constant$
Z
– depth
$The
relation between the skin depth(\delta) and decay constant (\beta) is $
$\delta = \frac{1}{\beta}-----(2)$
$Skin depth, \delta = 503.8\sqrt{\frac{\rho}{f}}-----(3)$
$Skin depth, \delta = 503.8\sqrt{\frac{\rho}{f}}-----(3)$
$\beta = \frac{1}{\delta}=\frac{1}{100}=0.01$
Z=75m
Substitute
in eq(1)
$\frac{A_{(75)}}{A_o}= e^{-\beta Z}= e^{-0.01 \times 75} = e^{-0.75}$
$\frac{A_{(75)}}{A_o}= e^{-\beta Z}= e^{-0.01 \times 75} = e^{-0.75}$
$ \frac{A_{(75)}}{A_o}=0.472$
$\therefore the ratio of the amplitudes= 0.472$
How could you find the skin depth without knowing resistivity value
ReplyDeleteHi srinu, in the above solution skin depth is given directly, just for idea I placed the formula. Here I'm not using frequency and resistivity to calculate the skin depth.
DeletePlease read question once again, and hopefully you will understand.
thank u sir,i got it
DeleteMfoegaeQgran_po_Omaha Kimberly Turner click
ReplyDeleteclick here
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