CSIR-NET 2013
1. Consider a 80 km
thick crust of, Vp-6 km/s overlying the mantle with P-velocity 8.0
km/s. If an earthquake occurs near surface, at which epicenter
distance the Pn will be first recorded on seismogram?
(1) 280 km
(2) 320 km
(3) 390 km
(4) 430 km
Solution:
Beyond about 200 km
there were two arrivals; the $P_g$ event was overtaken by another
arrival $(P_n)$ which had evidently travelled at higher speed.
Mohoroviçiç identified $P_g$ as the direct wave from the earthquake
and $P_n$ as a doubly refracted wave (equivalent to a head wave) that
travelled partly in the upper mantle. Mohoroviçiç calculated
velocities of 5.6 km/s for $P_g$ and 7.9 km/s for $P_n$
At Crossover
distance the Direct wave and refracted waves cross each other in t-x
plot, and reach at same time.
Crust thickness z =
80km
Velocity of the
first layer $V_1$= 6 km/s
Velocity of the
second layer $V_2$= 8 km/s
$x_{cross}= 2z
\sqrt{\frac{V_2+V_1}{V_2-V_1}}$
$x_{cross}= 2*80
\sqrt{\frac{8+6}{8-6}}$
$x_{cross}= 2*80
\sqrt{\frac{14}{2}}$
$x_{cross}= 2*80
\sqrt{7}$
$x_{cross}=
423.32km$
Reference : Fundamental of Geophysics, William Lowrie.
please solve this question Csir net 2019 dec-
ReplyDeleteThe travel time in a reflection survey over a reflector of velocity 4.0 km/sec underlain by a medium of velocity 2.40 km/sec is 1.0 sec. what will be travel time if the underlying medium has a velocity of 6.0 km/sec?
1)400ms 2)650ms 3)875 ms 4)1.0 sec
The correct answer is option (4)
In reflection we use only the first layer velocity...even if the second layer velocity is changed the the travell to me will not changed
ReplyDeleteyes correct.. it will depends on the first layer velocity not on the second layer velocity.
DeleteSir, is it not the critical distance... Because its the distance at which the first refracted wave arrives.
ReplyDeleteWe solved using crossover distance.
DeleteI tried using critical distance... The option is not there
Delete