GATE-2018
77.
A student interpreted a four layer Schlumberger resistivity sounding
data and obtained the resistivities (\rho) and thicknesses (h) as
follows: \rho_1=100 ohm m, \rho_2=20 ohm m, \rho_3=1500
ohm m and \rho_4=50 ohm m; h_1=50 m, h_2=10 m and h_3=20 m.
The same data is interpreted by another student who obtains
\rho_3=2000 ohm m. Then, according to the principle of equivalence,
the value of h_3 interpreted by the second student is ________m.
(All other model parameters estimated by both the students are the
same.)
Solution:
Principle
of equivalence: It is impossible to distinguish between two highly
resistive beds of different "h" and "\rho" values if the product
"h*\rho" is the same.
So,
The
first student h_3=20m
and
\rho_3 =1500 ohm m
The
second student \rho_3 =2000 ohm m
And what is the h_3 = ?
h_3*\rho_3
=h_3*\rho_3
20*1500
=h_3*2000
h_3*2000=20*1500
h_3=\frac{20*1500}{2000}
h_3=15
m
Reference: Applied Geophysics by W.M. Telford , L.P. Geldart and R.E.Sheriff.
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