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GATE_2018_77

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GATE-2018


77. A student interpreted a four layer Schlumberger resistivity sounding data and obtained the resistivities (\rho) and thicknesses (h) as follows: \rho_1=100 ohm m, \rho_2=20  ohm m, \rho_3=1500 ohm m and \rho_4=50 ohm m; h_1=50 m, h_2=10 m and h_3=20 m. The same data is interpreted by another student who obtains \rho_3=2000 ohm m. Then, according to the principle of equivalence, the value of h_3 interpreted by the second student is ________m. (All other model parameters estimated by both the students are the same.)

Solution:


Principle of equivalence: It is impossible to distinguish between two highly resistive beds of different "h" and "\rho" values if the product "h*\rho" is the same.

So,

The first student h_3=20m

and \rho_3 =1500 ohm m

The second student \rho_3 =2000 ohm m

And what is the h_3 = ?

h_3*\rho_3 =h_3*\rho_3

20*1500 =h_3*2000

h_3*2000=20*1500

h_3=\frac{20*1500}{2000}

h_3=15 m


Reference:  Applied Geophysics by W.M. Telford , L.P. Geldart and R.E.Sheriff.


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