35. The total amount of an element dissolved in the Ocean is $10^7$ kg and its removal rate from seawater is $10^5$ g/y. Under steady-state condition, the residence time of the element is
(1) 10^15 years
(2) 10^5 years
(3) 10^2 years
(4) 10^0.2 years
Solution:
Residence time is the average time that a substance remains in solution in seawater.
Residence Time (yrs.) = Total amount of ion in seawater (kg) / Input rate (kg/yr)
where,
Input rate = Avg. ion con. in rivers (kg/km3) x River discharge (km3/yr)
So, Total amount of ion dissolved in sea water is =$10^7 $kg
= $10^{10}$ g
Removal rate of sea water is =$10^5$ g/y
Residence Time (yrs.) = $\frac{10^{10}}{10^5}$ g/y
= $10^5$ grams
Reference:https://www.e-education.psu.edu/earth540/content/c3_p7.html
Solution:
Residence time is the average time that a substance remains in solution in seawater.
Residence Time (yrs.) = Total amount of ion in seawater (kg) / Input rate (kg/yr)
where,
Input rate = Avg. ion con. in rivers (kg/km3) x River discharge (km3/yr)
So, Total amount of ion dissolved in sea water is =$10^7 $kg
= $10^{10}$ g
Removal rate of sea water is =$10^5$ g/y
Residence Time (yrs.) = $\frac{10^{10}}{10^5}$ g/y
= $10^5$ grams
Reference:https://www.e-education.psu.edu/earth540/content/c3_p7.html
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