106.Gravity
anomaly values of 1.2,2,4 and 3.6 in m gals are located at distance coordinates
20,24 and 28 km, respectively ,along a gravity profile across a faulted
basement of limited throw. The depth to the basement (in km) is
A)
2
B)
2 √2
C)
2 √3
D)
4
Solution:
The relation between depth and half-width for a fault is given that,
$Z_c=1.0*X_{1/2}$
From figure the half-width of the fault is $X_{1/2}$ = 24-20 = 4 km
$Z_c=1.0*4$
$Z_c=4 km$
Reference:
Gravity and Magnetic Exploration Principles, Practices, and Applications by
William J. Hinze, Ralph R.B. Von Frese and Afif H.Saad
A question here. Why are we considering the midpoint of the inclined fault as its depth anyway? Any logical reason behind this? I tried to read from the reference book but it was not clear.
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