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GATE-2017


28. Given the Bouguer density of 2.8 g/cc , the Bouguer correction for a gravity station at an elevation of 30 m above the datum is _________________mGals.

(Thanks to Saroja)

Solution:

Formula:

Bouguer correction ({\triangle g}_{Bc})=2 \pi G\triangle \rho t

G= universal gravity constant = 6.67*10^{-11} m^{3}/kg s^{2}


\triangle\rho=2.8 gm /cc

    =2800 kg/ m^{3}

elevation t = 30 m

{\triangle g}_{Bc}=2 \pi G\triangle \rho t

     = 2*3.14*6.67*10^{-11}*2800*30 m^{3}/kg.s^{2}*kg/m^{3}*m

       = 3518554.8*10^{-11}m/s^{2}

       = 0.352*10^{-11+7}m/s^{2}

      =0.352*10^{-4} m/s^{2}

      =0.352*10^{-2}cm/s^{2}

   (Gal =1cm/s^2)

      =0.352*10^{-2}Gal

      = 0.352*10^{-2}*10^{3}mGal

      =3.52 mGal.

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