28.
Given the Bouguer density of 2.8 g/cc , the Bouguer correction for a
gravity station at an elevation of 30 m above the datum is
_________________mGals.
(Thanks to Saroja)
Solution:
Formula:
Bouguer
correction ({\triangle g}_{Bc})=2 \pi G\triangle \rho t
G=
universal gravity constant = 6.67*10^{-11} m^{3}/kg s^{2}
\triangle\rho=2.8
gm /cc
=2800
kg/ m^{3}
elevation
t = 30 m
{\triangle
g}_{Bc}=2 \pi G\triangle \rho t
=
2*3.14*6.67*10^{-11}*2800*30 m^{3}/kg.s^{2}*kg/m^{3}*m
=
3518554.8*10^{-11}m/s^{2}
=
0.352*10^{-11+7}m/s^{2}
=0.352*10^{-4}
m/s^{2}
=0.352*10^{-2}cm/s^{2}
(Gal =1cm/s^2)
=0.352*10^{-2}Gal
=
0.352*10^{-2}*10^{3}mGal
=3.52
mGal.
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