Q) Assume that the poisons solid is subjected to
a longitudinal stress while the transverse stress are zero. Then the young’s
modules ( E ) in terms of modules of rigidity (µ)will be___
(Thanks
to Chandrasekhar, ANU)
Solutions:
From
the relation
$\mu
=\frac{E}{2(1+\nu)}$
$\mu
=\frac{E}{2(1+0.25)}$ for poissons solid v =0.25
$\mu
=\frac{E}{2(1.25)}$
$\mu
=\frac{E}{2.5}$
$E=
2.5\times\mu$
Reference : Fundamental
of Geophysics, William Lowrie.
good
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