Q) Assume that the poisons solid is subjected to
a longitudinal stress while the transverse stress are zero. Then the young’s
modules ( E ) in terms of modules of rigidity (µ)will be___
(Thanks
to Chandrasekhar, ANU)
Solutions:
From
the relation
\mu
=\frac{E}{2(1+\nu)}
\mu
=\frac{E}{2(1+0.25)} for poissons solid v =0.25
\mu
=\frac{E}{2(1.25)}
\mu
=\frac{E}{2.5}
E=
2.5\times\mu
Reference : Fundamental
of Geophysics, William Lowrie.
good
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