Question: The Decay Constant of 235 U and 238 U are 9.848 * 10-10 /year and 1.551* 10-10 /year respectively. Calculate the half-life of the Uranium isotopes.
Solution:
We know the relation
between the half-life and the decay constant is
$t_{1/2}=\frac{ln(2)}{\lambda}=\frac{0.693}{\lambda}$
For
1. The Half-life of the Uranium 235 isotope is
$t_{1/2}=\frac{0.693}{9.848\times 10^{-10}}=0.070\times 10^{10}$
2. The Half-life of Uranium 238
isotope is
$t_{1/2}=\frac{0.693}{1.551\times 10^{-10}}=0.4468\times 10^{10}$
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