Calculation of true thickness of the bed

 101) What will be the approximate Precessional frequency of the signal, if the intensity of magnetic field is 30,000nT and gyromagnetic ratio value is $2.67513\times10^{8}S^{-1}T^{-1}$ ? 

 (Thanks to Chandrasekhar and Rajkumar, AKNU)

Solution:

          Given that

  Gyromagnetic ratio $\gamma_{p}=2.67513\times10^{8}S^{-1}T^{-1}$

Intensity of magnetic field $B_{t}$=30,000nT

          The Preccesional frequency of the signal can be defined as

$f=\frac{\gamma_{p}}{2\pi}B_{t}$-----------------------(1)

 By substituting the given values in the above equation we get

$f=\frac{\gamma_{p}}{2\pi}B_{t}$

 

$f=(\frac{2.67513\times10^{8}}{2\times3.14})(30,000nT)$

 

  $f=\frac{2.67513\times10^{8}\times3\times10^{4}nT}{2\times3.14}$

 

 $f=\frac{2.67513\times10^{8}\times3\times10^{4}\times10^{-9}T}{2\times3.14}$                        [ since $1nT= 10^{-9}T$]

 

 $f=\frac{2.67513\times3\times10^{3}T}{2\times3.14}(S^{-1}\times T^{-1} \times T)$

 

 $f=1277.928 Hz$

Reference : Fundamental of Geophysics, William Lowrie.