Calculation of true thickness of the bed

 25. A confined aquifer with a uniform saturated thickness of 10 m has hydraulic conductivity of $10^{-2}$ cm/s. Considering a steady flow, the transmissivity of the aquifer in m2/day is _________________ (rounded off to one decimal place).

 

Solution:

 

Thickness =10 m

Hydraulic conductivity of $10^{-2}$ cm/s

 

convert hydraulic conductivity units cm/s into m/day

 

            = $10^{-2}*10^{-2} m/s$

 

           = $10^{-4} m/s$

 

1day =86400 sec

 

        =$10^{-4}*86400 m/day$

 

        =8.64 m/day

 

Transmissivity is directly proportional to horizontal hydraulic conductivity Ki and thickness di.

Therefore,

 

Transmissivity $T= K d$

 

$T= 8.64 * 10 m^2/s$

 

$T= 86.4 m^2/s$

 

Extra information:

https://gpsurya.blogspot.com/2024/04/fundamentals-of-hydrology.html