CSIR-NET
50. A seismic ray incident at an angle of 30 degrees is refracted at
an angle of 45 degrees . If the velocity in the upper layer is V1=2.0
km/s, then the velocity in the underlying layer is close to
an angle of 45 degrees . If the velocity in the upper layer is V1=2.0
km/s, then the velocity in the underlying layer is close to
A) 2.2 km/s
B) 2.4 km/s
C) 2.6 km/s
D) 2.8 km/s
Solution:
From
Snell’ s law
sini
/sinr = V1/
V2-------------(1)
i=
incident angle = 300
r=
refracted angle = 450
V1=
velocity of the upper layer = 2 km/s
V2=
velocity of the underlying layer = ?
substitute
above values in eq(1)
sin
300/
sin 450
= 2/ V2
V2=
2 sin450
/ sin300
V2
= ( (2 * 1/√2)
/ (1/2) )
V2
= 2* 1.414
V2=
2.8 km/s
Therefore,
velocity of the underlying layer (V2)
= 2.8 km/s
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