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GATE-2008 (36)

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GATE-2008

Q36. An X-ray benm of wavelength(λ) =1.541 A0 is incident on a 

cubic crystal having lattice spacing of 4 A0. What will be its 2θ 

value (where θ is the glancing angle) on X- ray diffractogram?


A) 11.10 A0
         
B) 20.10 A0   
     
C) 22.20 A0  
                      
D) 22.20 A0


Solution:



Formula:


Bragg’s law===> 2*d* sinθ = n*λ-------------------(1)


wavelength (λ)= 1.541 A0


lattice spacing (d) = 4 A0


Angle between the incident angle and the surface of the crystal (θ) = ?


==> 2*d* sinθ= n*λ


==> sinθ = (n*λ) / (2*d)


==> sinθ = (1*1.541) / (2* 4)


==> sinθ = 0.1926


==> θ= sin-1 (0.1926)


==> θ= 11.1045


Then, what is the value of 2θ (given problem)


==> 2θ= 2* 11.1045



==> 2θ=22.209 



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