GATE-2018 (24) :Wyllie – Time average equation

Gate_2019

84) A vibroseis source sweeps acoustic signal in the frequency range 10 Hz – 100Hz. The maximum sampling interval to correctly recover the recorded signal will be _______ milli seconds.

(Thanks to Chandra Sekhar, ANU)

Solution:

Given the frequency range (f) = 10 Hz -100 Hz

Sampling interval($t_{s}$) = ?

The sampling frequency $(f_{s}) = 2 * f_{m}$

Maximum frequency is given $(f_m)$ = 100 Hz

Therefore The sampling frequency $(f_{s}) = 2 * f_{m}$

                                                                 = 2*100

                                                                 =200 Hz

The Sampling interval$(t_{s}) = \frac{1}{f_{s}}$

                                              = $\frac{1}{200}$

                                              = 0.005 sec

Sampling interval($t_{s}$) = 5 milli seconds

Referance: https://community.sw.siemens.com/s/article/digital-signal-processing-sampling-rates-bandwidth-spectral-lines-and-more