Gate_2019
84)
A vibroseis source sweeps acoustic signal in the frequency range 10
Hz – 100Hz. The maximum sampling interval to correctly recover the
recorded signal will be _______ milli seconds.
(Thanks to Chandra Sekhar, ANU)
Solution:
Given
the frequency range (f) = 10 Hz -100 Hz
Sampling
interval(t_{s}) = ?
The
sampling frequency (f_{s}) = 2 * f_{m}
Therefore
The sampling frequency (f_{s}) = 2 * f_{m}
= 2*100
=200 Hz
The
Sampling interval(t_{s}) = \frac{1}{f_{s}}
= \frac{1}{200}
= 0.005 sec
Sampling
interval(t_{s}) = 5 milli seconds
Referance: https://community.sw.siemens.com/s/article/digital-signal-processing-sampling-rates-bandwidth-spectral-lines-and-more
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