29) A scalar potential field in 3D space is expressed as U(x,y,z) = x^{2}+yz^{2}. The magnitude of the maximum rate of change in U(x,y,z) at a point (1,1,2) is____
(Thanks to Chandrasekhar, ANU)
Solution:
Given the function U(x,y,z) = x^{2}+yz^{2}
First calculate the first derivatives of the function
\frac{\partial U}{\partial x}=2x
\frac{\partial U}{\partial y}=z^{2}
\frac{\partial U}{\partial z}=2yz
Then
\triangledown U(x,y,z) = < \frac{\partial U}{\partial x} , \frac{\partial U}{\partial y} , \frac{\partial U}{\partial z}>
\triangledown U(x,y,z) = < 2x,z^{2},2yz>
\triangledown U(1,1,2) = < 2(1),(2)^{2},2(1)(2)>
\triangledown U(1,1,2) = < 2,4,4>
For calculating the magnitude of the maximum rate of change is
\mid\triangledown U(1,1,2)\mid=\sqrt{2^{2}+4^{2}+4^{2}}
\mid\triangledown U(1,1,2)\mid=\sqrt{4+16+16}
\mid\triangledown U(1,1,2)\mid=\sqrt{36}
\mid\triangledown U(1,1,2)\mid=6
The maximum rate of change in U(x,y,z) at a point (1,1,2) for the function x^{2}+yz^{2} is 6
Please give Reference.
ReplyDeleteThanks to chandrasekhar...
DeleteReference:
https://youtu.be/xBKhPZ5RgzQ
Thank you 🙏 very much sir
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