29) A scalar potential field in 3D space is expressed as U(x,y,z) = $ x^{2}+yz^{2}$. The magnitude of the maximum rate of change in U(x,y,z) at a point (1,1,2) is____
(Thanks to Chandrasekhar, ANU)
Solution:
Given the function U(x,y,z) = $ x^{2}+yz^{2}$
First calculate the first derivatives of the function
$\frac{\partial U}{\partial x}=2x$
$\frac{\partial U}{\partial y}=z^{2}$
$\frac{\partial U}{\partial z}=2yz$
Then
$\triangledown U(x,y,z) = < \frac{\partial U}{\partial x} , \frac{\partial U}{\partial y} , \frac{\partial U}{\partial z}>$
$\triangledown U(x,y,z) = < 2x,z^{2},2yz>$
$\triangledown U(1,1,2) = < 2(1),(2)^{2},2(1)(2)>$
$\triangledown U(1,1,2) = < 2,4,4>$
For calculating the magnitude of the maximum rate of change is
$\mid\triangledown U(1,1,2)\mid=\sqrt{2^{2}+4^{2}+4^{2}}$
$\mid\triangledown U(1,1,2)\mid=\sqrt{4+16+16}$
$\mid\triangledown U(1,1,2)\mid=\sqrt{36}$
$\mid\triangledown U(1,1,2)\mid=6$
The maximum rate of change in U(x,y,z) at a point (1,1,2) for the function $ x^{2}+yz^{2}$ is 6
Please give Reference.
ReplyDeleteThanks to chandrasekhar...
DeleteReference:
https://youtu.be/xBKhPZ5RgzQ