Processing math: 100%

Introduction to gpsurya blog

Dear Friends, In this blog you will find around 320 solved Geophysics GATE and CSIR-NET and other competitive exams solutions with a better explanation. Please follow and share if you like it. Thanks, gpsurya and group

GATE-2019

Post a Comment

 24. Given that \left( \frac{18_{O}}{16_{O}}\right)_{V-SMOW}=2005.2*10^{-6},the \frac{18_{O}}{16_{O}}  of a sample whose (\delta^{18}O)_{V-SMOW}=+25% is__________      *10^{-6} (round off to 1 decimal place).

     

Thanks to Saroja

Solution:

 

\left( \frac{18_{o}}{16_{o}}\right)_{sample}=?

 

oxygen isotope ratio (\delta^{18}0)

 

 (\delta^{18}O) =\left(\frac{\left(\frac{18_{O}}{16_{O}}\right)_{sample}}{\left(\frac{18_{O}}{16_{O}}\right)_{standard}}-1\right)1000

 

25=\left(\frac{\left(\frac{18_{O}}{16_{O}}\right)_{sample}}{\left(\frac{18_{O}}{16_{O}}\right)_{standard}}-1\right)1000

 

\frac{25}{1000}=\left(\frac{\left(\frac{18_{O}}{16_{O}}\right)_{sample}}{\left(\frac{18_{O}}{16_{O}}\right)_{standard}}-1\right)

 

\frac{\left( \frac{18_{O}}{16_{O}}\right)_{sample}}{2005.2*10^{-6}}=0.025+1 =1.025


\left( \frac{18_{O}}{16_{O}}\right)_{sample}=2055.33*10^{-6}


Related Posts

There is no other posts in this category.

Post a Comment

Subscribe Our Newsletter