29) On a 1:10,000 scale map the length of a
fault trace on a horizontal plane is represented as 5 cm. The same on a
1:25,000 scale vertical aerial photograph is ____cm
(Thanks
to Chandrasekhar, ANU)
Solution:
The
scale of first map is 1 cm = 10,000 cm,
The
length of the fault trace from the first scale is 5 cm that is the actual
length of the fault trace of ground is 50,000 cm.
Now
the scale of the second map is 1 cm = 25,000 cm.
Now
the length of 50,000 cm fault is shown on map as? cm.
1=
25,000 then
?(some
X) = 50,000
Therefore
X= $\frac{50000}{25000}$
X=
2 cm.
The
length of the fault on the second map is 2 cm.
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