Q. A strong earthquake that occurred in the Indian Ocean settles off a tsunami wave propagating towards Vishakhapatnam. Calculate the velocity of wave (Km/h) and time to reach the Vishakhapatnam coast which is an angular distance of 6 degrees from the epicenter. (Average depth of the Indian Ocean is 4 km).
Solution:
The
Velocity (V) of the tsunami is related to the Ocean depth ‘d’ is given by
V=\sqrt{gd}
g-acceleration
due to gravity =9.8 m/s^2
d-
Average depth of the Indian Ocean = 4000 m
V=\sqrt{9.82\times
4000}
V=\sqrt{39,240}
V=198
m/s
V=713
Km/hr
Time
taken for the tsunami to reach the Visakhapatnam Coast is
time
(t)=\frac{Distance}{Velocity}
t=\frac{6\times
111}{713}
t=0.934 hr
Extra information:
1^{0}
= 111km
6^{0}=6\times
111
Reference : Fundamental of Geophysics, William Lowrie.
666/713=0.98 something but here its showing 1.33
ReplyDeleteThanks, I will correct it.
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