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Expected GATE-2022 Geophysics Solution (7)

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 Q. A strong earthquake that occurred in the Indian Ocean settles off a tsunami wave propagating towards Vishakhapatnam. Calculate the velocity of wave (Km/h) and time to reach the Vishakhapatnam coast which is an angular distance of 6 degrees from the epicenter. (Average depth of the Indian Ocean is 4 km).


Solution:

The Velocity (V) of the tsunami is related to the Ocean depth ‘d’ is given by

V=\sqrt{gd}

g-acceleration due to gravity =9.8 m/s^2

d- Average depth of the Indian Ocean = 4000 m

V=\sqrt{9.82\times 4000}

V=\sqrt{39,240}

V=198 m/s

V=713 Km/hr

Time taken for the tsunami to reach the Visakhapatnam Coast is

time (t)=\frac{Distance}{Velocity}

t=\frac{6\times 111}{713}  

t=0.934 hr

 



Extra information:

1^{0} = 111km

6^{0}=6\times 111

 

Reference : Fundamental of Geophysics, William Lowrie.

 

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