97. In a seismic reflection survey, the inferred upper and lower layer velocities are 2 km/s and 6 km/s, respectively. The depth of the refractor is 0.5 km. What will be the crossover distance?
a) 2828m b)
1414m c) 707m d) 353.5m
(Thanks to Pragnath, AU)
Solution:
$X_{~crossover}=2Z*\sqrt{~\frac{V_{2}+V_{1}}{V_{2}-V_{1}}}$
Given that $Z=0.5km$ $V_{1}=2 Km/s$ $V_{2}=6 Km/s$
$X_{~crossover}=2(0.5)*\sqrt{~\frac{6+2}{6-2}}$
$X_{~crossover}=1*\sqrt{~\frac{8}{4}}$
$X_{~crossover}=\sqrt{2}$
$X_{~crossover}=1.414 km$ or
$X_{~crossover}=1414 meters$
Similar problems links,
https://gpsurya.blogspot.com/2019/12/csir-net-2013-june.html
https://gpsurya.blogspot.com/2016/04/csir-net-2015-dec-90.html
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