116. What will be the approximate skin depth of electromagnetic waves of frequency 1 kHz in a conductor having conductivity 100 S/m ?
a) 16 meters
b). 1.6 meters
c). 016 meters
d). 0.016 meter
(Thanks to Pragnath, AU)
Solution: -
Skin depth formula D = 503.8 *
\sqrt{(\frac{\rho}{f})}
Given that (conductivity)
~\sigma= 100 S/m~
(conductivity) \sigma=\frac{1}{\rho (resistivity)}
\rho=\frac{1}{100}
D = 503.8 * \sqrt{(\frac{1/100}{1000})}
D=
503.8*\frac{\sqrt{0.01}}{\sqrt{1000}}
D= 503.8*\frac{{0.1}}{{31.622}}
D= 503.8*0.0031623
D\approx1.6
The answer is option (b)
1.6 meter
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