Calculation of true thickness of the bed

 22. The transmission coefficient for the vertically incident seismic wave at the interface between layer 1 and layer 2 is?

Layer1= $V_{1}=1000 m/s,~~~~\rho_{1}=1200kg/m^{3}$

Layer2= $V_{2}=1500 m/s,~~~~\rho_{2}=1300kg/m^{3}$

$V_{1}~V_{2}=P-wave~velocity,~~~~\rho_{1},\rho_{2}=densities$

(Thanks to Pragnath, AU)

Solution:        

we know that Transmission coefficient $(T~C)=\frac{2(V_{1}*\rho_{1})}{(V_{2}*\rho_{2})+(V_{1}*\rho_{1})}----(1)$

Substituting above values in equation (1)

$T~C=\frac{2(1000*1200)}{(1500*1300)+(1000*1200)}$

$T~C=\frac{(24*10^{5})}{(195*10^4)+(24*10^5)}$

$T~C=\frac{24*10^{5}}{(435*10^4)}$

$T~C=0.761$