24. A seismic reflection survey is carried out over a 1500 m thick horizontal layer with a P-wave velocity of 2000 m/s. The travel time of a reflected wave at a surface detector placed 1000m from a surface source is _______ milliseconds.
(Thanks
to Pragnath, AU)
Solution:
Given that V_{p}=2000
m/s=2 Km/s~;
d( depth)=1500 m=1.5
Km;
x(offset distance)=1000m=1
Km.
T^{2}=\frac{X^{2}}{V^{2}}+(\frac{2D}{V})^2
T^{2}=\frac{1^{2}}{2^{2}}+(\frac{2(1.5)}{2})^2
T^{2}=\frac{1}{4}+(\frac{3}{4})^2
T^{2}=0.25+(1.5)^2
T^{2}=0.25+2.25
T=\sqrt{2.5}
T=1.581 seconds
T=1581.13~milliseconds
Therefore, the travel
time is 1581 milliseconds
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